Chemical Engineering Thermodynamics (MCQs)

For spontaneous changes in an isolated system (S = entropy)

  • A. Ds = 0
  • B. Ds <0
  • C. Ds > 0
  • D. Ds = Constant
Answer: Option C.
Explanation: 
By second law of thermodynamics the TdS≥δQ
For an isolated system δQ=0
⇒ for an irreversible (nothing but spontaneous process) dS>0 and for an reversible (or the system at equilibrium) dS=0

Leave a Reply

Your email address will not be published. Required fields are marked *

Back to top button