Chemical Engineering Thermodynamics (MCQs)

For spontaneous changes in an isolated system (S = entropy)

  • A. Ds = 0
  • B. Ds <0
  • C. Ds > 0
  • D. Ds = Constant
Answer: Option C.
Explanation: 

By second law of thermodynamics the TdS≥δQ

For an isolated system δQ=0

⇒ for an irreversible (nothing but spontaneous process) dS>0 and for an reversible (or the system at equilibrium) dS=0

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