Irrigation Engineering

Fundamental momentum equation for a hydraulic jump, is

  • A. D₁² – D₂² = (2q/g) × (V₁ – V₂)
  • B. D₂² – D₁² = (2q/g) × (V – V₂)
  • C. D₁² – D₂² = (2q/g) × (V₂ – V₁)
  • D. D₁² + D₂² = (2q/g) × (V₂ – V₁)
Answer: Option B.
Explanation: 

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