Chemical Engineering Thermodynamics

Joule-Thomson co-efficient for a perfect gas is

  • A. Zero
  • B. Positive
  • C. Negative
  • D. None of these
Answer: Option A.
Explanation: 

For a perfect gas since, the enthalpy depends only on temperature and the joule Thomson coefficient which is ratio of temperature change to pressure change at constant enthalpy. Since for an perfect gas the enthalpy remaining constant leads to temperature constancy the joule Thomson coefficient becomes zero.

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